ChinaZip v2.0的注册码算法(初学者)
dyiyd
很少写破解心得，不足之处请指正。
为什么要选择ChinaZip呢？因为ChinaZip的算法比较简单，非常适合初学者。
能让每一个初学者都能学会如何分析注册码的算法，写出注册机。（是谁在笑我...）^o^
由于本文是针对初学者，所以下面的破解过程我尽量写的详细一些。 软件介绍：
中华压缩(ChinaZip) V2.0
中华压缩是一个国产的压缩、解压缩软件，暂时只支持 zip 压缩格式，
正式版本将逐步支持RAR,ARJ,CAB 等更多的压缩格式。软件的界面、操作习惯、
程序快捷键将完全兼容 WinZip。 下载地：
http://www.soft999.com/download2/ChinaZip.exe 软件保护：
1.Aspack1.07b
2.注册码保护
----------------- 使用工具：
1.UnAspack v1.0.9.1
2.Trw2000 v1.22
3.W32dsm v8.9黄金版
4.Crackcode2000
5.VB 5.0
-------------------------
现在开始破解喽！............... 1.首先运行ChinaZip.exe
2.在帮助菜单下找到注册部分 3.用户名：dyiyd(你可输入你的名字）
注册码：98989898 4.按确定后出现“您的注册码不正确!” (这可是破解的线索哦！)
5.将ChinaZip.exe用UnAspack v1.0.9.1脱壳(有兴趣的朋友可手动脱壳。我比较懒....^o^)
6.w32dsm v8.9黄金版载入已脱壳的ChinaZip.exe
7.搜索“您的注册码不正确”字符串。很快便找到了....
8.下面开始静态分析...从“您的注册码不正确!”向上看
--------------------------------------- * Possible StringData Ref from Code Obj ->"?�蹕]"
|
:004D1DD3 68D51E4D00 push 004D1ED5
:004D1DD8 64FF30 push dword ptr fs:[eax]
:004D1DDB 648920 mov dword ptr fs:[eax], esp
:004D1DDE A1CC6D4E00 mov eax, dword ptr [004E6DCC]
:004D1DE3 8B00 mov eax, dword ptr [eax]
:004D1DE5 8B10 mov edx, dword ptr [eax]
:004D1DE7 FF92D8000000 call dword ptr [edx+000000D8]
:004D1DED 48 dec eax
:004D1DEE 0F85B6000000 jne 004D1EAA
:004D1DF4 8D55FC lea edx, dword ptr [ebp-04]
:004D1DF7 A1CC6D4E00 mov eax, dword ptr [004E6DCC]
:004D1DFC 8B00 mov eax, dword ptr [eax]
:004D1DFE 8B80E0020000 mov eax, dword ptr [eax+000002E0]
:004D1E04 E87F10F6FF call 00432E88------------/*取出你输入的用户名*/
:004D1E09 8D4DF8 lea ecx, dword ptr [ebp-08]
:004D1E0C 8B55FC mov edx, dword ptr [ebp-04]---/*[ebp-04]存放是
你的用户名*/
:004D1E0F 8BC3 mov eax, ebx
:004D1E11 E8D6FDFFFF call 004D1BEC-----------/*注册码计算部分*/
:004D1E16 8D55F4 lea edx, dword ptr [ebp-0C]
:004D1E19 A1CC6D4E00 mov eax, dword ptr [004E6DCC]
:004D1E1E 8B00 mov eax, dword ptr [eax]
:004D1E20 8B80E4020000 mov eax, dword ptr [eax+000002E4]
:004D1E26 E85D10F6FF call 00432E88-----------/*取出你输入的注册码*/
:004D1E2B 8B45F4 mov eax, dword ptr [ebp-0C]----/*[ebp-0C]存放
你输入的注册码*/
:004D1E2E 8B55F8 mov edx, dword ptr [ebp-08]----/*[ebp-08]存放
真正的注册码*/
:004D1E31 E89A22F3FF call 004040D0---/*这个Call一定是注册码比较处*/
:004D1E36 7568 jne 004D1EA0----/*我们来到这里。哈哈！有点儿意
思了吧？*/
/*这里要跳就跳过了所有注册成功的信息*/
:004D1E38 A1306F4E00 mov eax, dword ptr [004E6F30]
:004D1E3D 8B00 mov eax, dword ptr [eax]
:004D1E3F 8B8008040000 mov eax, dword ptr [eax+00000408]
:004D1E45 B201 mov dl, 01
:004D1E47 E89CB3FDFF call 004AD1E8
:004D1E4C 8D55F0 lea edx, dword ptr [ebp-10]
:004D1E4F A120704E00 mov eax, dword ptr [004E7020]
:004D1E54 8B00 mov eax, dword ptr [eax]
:004D1E56 E8E1EEF7FF call 00450D3C
:004D1E5B 8D45F0 lea eax, dword ptr [ebp-10] * Possible StringData Ref from Code Obj ->" - 注册用户!"
|
:004D1E5E BAEC1E4D00 mov edx, 004D1EEC
:004D1E63 E86021F3FF call 00403FC8
:004D1E68 8B55F0 mov edx, dword ptr [ebp-10]
:004D1E6B A1306F4E00 mov eax, dword ptr [004E6F30]
:004D1E70 8B00 mov eax, dword ptr [eax]
:004D1E72 E84110F6FF call 00432EB8
:004D1E77 6A40 push 00000040 * Possible StringData Ref from Code Obj ->"注册成功！"
|
:004D1E79 B9FC1E4D00 mov ecx, 004D1EFC * Possible StringData Ref from Code Obj ->"谢谢您的宝贵支持."
|
:004D1E7E BA081F4D00 mov edx, 004D1F08
:004D1E83 A120704E00 mov eax, dword ptr [004E7020]
:004D1E88 8B00 mov eax, dword ptr [eax]
:004D1E8A E8E1F4F7FF call 00451370
:004D1E8F A174F05000 mov eax, dword ptr [0050F074]
:004D1E94 C7803402000001000000 mov dword ptr [ebx+00000234], 00000001
:004D1E9E EB0A jmp 004D1EAA * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1E36(C)-----------/*注意这个偏移地址，向上找到此偏移地址*/
| * Possible StringData Ref from Code Obj ->"您的注册码不正确!"
|
:004D1EA0 B8241F4D00 mov eax, 004D1F24
:004D1EA5 E84661F8FF call 00457FF0
-------------------------------------------------------- 9.到现在为止我们只要知道这个Call
:004D1E31 E89A22F3FF call 004040D0--/*这个Call一定是注册码比较处*/
如果用Trm2000跟踪的话,按F8进入 :004040D0 53 push ebx
:004040D1 56 push esi
:004040D2 57 push edi
:004040D3 89C6 mov esi, eax
:004040D5 89D7 mov edi, edx
:004040D7 39D0 cmp eax, edx-----/*这是注册码的比较核心
eax是你输入的注册码
edx是真正的注册码
(下面我们可用这个地方用
CRACKCODE2000做个注册机)*/
:004040D9 0F848F000000 je 0040416E
:004040DF 85F6 test esi, esi
:004040E1 7468 je 0040414B
:004040E3 85FF test edi, edi
:004040E5 746B je 00404152
:004040E7 8B46FC mov eax, dword ptr [esi-04]
:004040EA 8B57FC mov edx, dword ptr [edi-04]
:004040ED 29D0 sub eax, edx
:004040EF 7702 ja 004040F3
:004040F1 01C2 add edx, eax
10.运行Trw2000,在运行ChinaZip.exe重复2、3步
11.按Ctrl-N呼出Trw2000
下断点bpx 4d1e31
按确定后程序立刻被Trw2000接管
下命令d edx 哈哈你看到什么?......注册码？^_^
至此我们已经知道了注册码，但是这并不是我们的最终目的。我们是想知道他是如何计算出
来的？往下看吧^_^ 12.重复10步.....
下断点bpx 004D1E11 我们来到这里
:004D1E09 8D4DF8 lea ecx, dword ptr [ebp-08]
:004D1E0C 8B55FC mov edx, dword ptr [ebp-04]--------------/*[eb
p-04]存放是你的用户名*/
:004D1E0F 8BC3 mov eax, ebx
:004D1E11 E8D6FDFFFF call 004D1BEC----------------------------/*注
册码计算部分*/
:004D1E16 8D55F4 lea edx, dword ptr [ebp-0C]
:004D1E19 A1CC6D4E00 mov eax, dword ptr [004E6DCC]
:004D1E1E 8B00 mov eax, dword ptr [eax] 按F8进入call 004D1BEC来到
* Referenced by a CALL at Address:
|:004D1E11
|
:004D1BEC 55 push ebp
:004D1BED 8BEC mov ebp, esp
:004D1BEF 6A00 push 00000000
:004D1BF1 6A00 push 00000000
:004D1BF3 6A00 push 00000000
:004D1BF5 6A00 push 00000000
:004D1BF7 6A00 push 00000000
:004D1BF9 6A00 push 00000000
:004D1BFB 6A00 push 00000000
:004D1BFD 53 push ebx
:004D1BFE 56 push esi
:004D1BFF 57 push edi
:004D1C00 894DF8 mov dword ptr [ebp-08], ecx
:004D1C03 8955FC mov dword ptr [ebp-04], edx
:004D1C06 8B45FC mov eax, dword ptr [ebp-04]
:004D1C09 E86625F3FF call 00404174
:004D1C0E 33C0 xor eax, eax
:004D1C10 55 push ebp * Possible StringData Ref from Code Obj ->"?�鉤媇婾?
|
:004D1C11 68D41C4D00 push 004D1CD4
:004D1C16 64FF30 push dword ptr fs:[eax]
:004D1C19 648920 mov dword ptr fs:[eax], esp
:004D1C1C 33F6 xor esi, esi
:004D1C1E 8D45F4 lea eax, dword ptr [ebp-0C]
:004D1C21 8B55FC mov edx, dword ptr [ebp-04]
:004D1C24 E8AF21F3FF call 00403DD8
:004D1C29 8B45F4 mov eax, dword ptr [ebp-0C]
:004D1C2C E88F23F3FF call 00403FC0-----------------------------/*确
定注册码的长度*/
:004D1C31 8BF8 mov edi, eax------------------------------/*将
注册码的长度(Eax)作为循环次数
保存在Edi当中*/
:004D1C33 85FF test edi, edi
:004D1C35 7E57 jle 004D1C8E------------------------------/*检
查用户名是否为空值若是则跳*/
:004D1C37 BB01000000 mov ebx, 00000001-------------------------/*将
Ebx赋值1(表示弟1次循环） * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1C8C(C)
|
:004D1C3C 8B45F4 mov eax, dword ptr [ebp-0C]---------------/*将
用户名取出*/
:004D1C3F 8A4418FF mov al, byte ptr [eax+ebx-01]-------------/*将
第1位的AscII码取出，结果保存在al中*/
:004D1C43 E858FFFFFF call 004D1BA0-----------------------------/*判
断该AscII中的数是否为素数(我们将在下面详解)*/
:004D1C48 84C0 test al, al-------------------------------/*若
是al=1 若不是al=0*/
:004D1C4A 7425 je 004D1C71-------------------------------/*al
=0跳转*/
:004D1C4C 8D45E8 lea eax, dword ptr [ebp-18]
:004D1C4F 8B55F4 mov edx, dword ptr [ebp-0C]
:004D1C52 8A541AFF mov dl, byte ptr [edx+ebx-01]
:004D1C56 E88D22F3FF call 00403EE8-----------------------------/*
:004D1C5B 8B45E8 mov eax, dword ptr [ebp-18]
:004D1C5E 8D55EC lea edx, dword ptr [ebp-14]
:004D1C61 E8166DF3FF call 0040897C-----------------------------/*这
三个Call将素数提出并且转换成大写*/
:004D1C66 8B55EC mov edx, dword ptr [ebp-14]
:004D1C69 8D45F0 lea eax, dword ptr [ebp-10]
:004D1C6C E85723F3FF call 00403FC8-----------------------------/*
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1C4A(C)
|
:004D1C71 83FB01 cmp ebx, 00000001-------------------------/*比是否为第1次循环*/
:004D1C74 740A je 004D1C80-------------------------------/*若
第1次循环则跳转*/
:004D1C76 8B45F4 mov eax, dword ptr [ebp-0C]---------------/*将
用户名转移到Eax中*/
:004D1C79 0FB64418FE movzx eax, byte ptr [eax+ebx-02]----------/*取
出1位AscII码*/
:004D1C7E EB06 jmp 004D1C86------------------------------/*无
条件转移到004D1C86*/ * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1C74(C)
|
:004D1C80 8B45F4 mov eax, dword ptr [ebp-0C]---------------/*将
用户名转移到Eax中*/
:004D1C83 0FB600 movzx eax, byte ptr [eax]-----------------/*将
用户名第1位的AscII码移到Eax中*/ * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1C7E(U)
|
:004D1C86 8D748612 lea esi, dword ptr [esi+4*eax+12]---------/*[e
si+4*eax+12]是注册码的计算公式
计算结果保存在Esi当中*/
:004D1C8A 43 inc ebx-----------------------------------/*当
前循环次数+1*/
:004D1C8B 4F dec edi-----------------------------------/*总
循环次数-1*/
:004D1C8C 75AE jne 004D1C3C------------------------------/*ed
i不等于0转移*/ * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1C35(C)
|
:004D1C8E 8D55E4 lea edx, dword ptr [ebp-1C]
:004D1C91 8BC6 mov eax, esi------------------------------/*将
Esi中的运算结果移至Eax中*/
:004D1C93 E8A870F3FF call 00408D40
:004D1C98 8B4DE4 mov ecx, dword ptr [ebp-1C]
:004D1C9B 8D45F4 lea eax, dword ptr [ebp-0C]
:004D1C9E 8B55F0 mov edx, dword ptr [ebp-10]
:004D1CA1 E86623F3FF call 0040400C-----------------------------/*将
运算结果转换成字符串
将上面AscII码为素数的字母+字符串
这就是注册码*/----终于算完了^o^
:004D1CA6 8B45F8 mov eax, dword ptr [ebp-08]
:004D1CA9 8B55F4 mov edx, dword ptr [ebp-0C]
:004D1CAC E8E320F3FF call 00403D94
:004D1CB1 33C0 xor eax, eax
:004D1CB3 5A pop edx
:004D1CB4 59 pop ecx
:004D1CB5 59 pop ecx
:004D1CB6 648910 mov dword ptr fs:[eax], edx * Possible StringData Ref from Code Obj ->"_[迕缷jjS乩h "
|
:004D1CB9 68DB1C4D00 push 004D1CDB * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1CD9(U)
|
:004D1CBE 8D45E4 lea eax, dword ptr [ebp-1C]
:004D1CC1 BA05000000 mov edx, 00000005
:004D1CC6 E89920F3FF call 00403D64
:004D1CCB 8D45FC lea eax, dword ptr [ebp-04]
:004D1CCE E86D20F3FF call 00403D40
:004D1CD3 C3 ret---------------------------------------/*退
出子程序*/ 至于判断是否为素数的算法也很简单：
按F8进入 call 004D1BA0
* Referenced by a CALL at Address:
|:004D1C43
|
:004D1BA0 55 push ebp
:004D1BA1 8BEC mov ebp, esp
:004D1BA3 51 push ecx
:004D1BA4 53 push ebx
:004D1BA5 56 push esi
:004D1BA6 8845FF mov byte ptr [ebp-01], al
:004D1BA9 C645FD02 mov [ebp-03], 02
:004D1BAD C645FE01 mov [ebp-02], 01
:004D1BB1 8A4DFF mov cl, byte ptr [ebp-01]
:004D1BB4 49 dec ecx
:004D1BB5 80E902 sub cl, 02
:004D1BB8 722A jb 004D1BE4
:004D1BBA 41 inc ecx
:004D1BBB B302 mov bl, 02--------------------------------/*bl
=2*/ * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1BE2(C)
|
:004D1BBD 33C0 xor eax, eax
:004D1BBF 8A45FF mov al, byte ptr [ebp-01]-----------------/*将
用户名的1位AscII码移至al*/
:004D1BC2 33D2 xor edx, edx
:004D1BC4 8AD3 mov dl, bl--------------------------------/*将
Bl-->dl*/
:004D1BC6 8BF2 mov esi, edx------------------------------/*将
edx-->esi*/
:004D1BC8 33D2 xor edx, edx------------------------------/*ed
x清零(异或）*/
:004D1BCA F7F6 div esi-----------------------------------/*ea
x/esi结果保存在eax余数保存在edx*/
:004D1BCC 85D2 test edx, edx-----------------------------/*检
查是否有余数*/
:004D1BCE 7503 jne 004D1BD3------------------------------/*若
有则跳*/
:004D1BD0 FE45FD inc [ebp-03] * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1BCE(C)
|
:004D1BD3 807DFD02 cmp byte ptr [ebp-03], 02
:004D1BD7 7606 jbe 004D1BDF
:004D1BD9 C645FE00 mov [ebp-02], 00
:004D1BDD EB05 jmp 004D1BE4 * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1BD7(C)
|
:004D1BDF 43 inc ebx----------------------------------/*edx
+1*/
:004D1BE0 FEC9 dec cl
:004D1BE2 75D9 jne 004D1BBD-------------------------- -------------------------------------------------------------------------------- * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1BCE(C)
|
:004D1BD3 807DFD02 cmp byte ptr [ebp-03], 02
:004D1BD7 7606 jbe 004D1BDF
:004D1BD9 C645FE00 mov [ebp-02], 00
:004D1BDD EB05 jmp 004D1BE4 * Referenced by a (U)nconditional or (C)onditional Jump at Address:
|:004D1BD7(C)
|
:004D1BDF 43 inc ebx----------------------------------/*edx
+1*/
:004D1BE0 FEC9 dec cl
:004D1BE2 75D9 jne 004D1BBD-----------------------------/不等
于0跳*/ * Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
|:004D1BB8(C), :004D1BDD(U)
|
:004D1BE4 8A45FE mov al, byte ptr [ebp-02]
:004D1BE7 5E pop esi
:004D1BE8 5B pop ebx
:004D1BE9 59 pop ecx
:004D1BEA 5D pop ebp
:004D1BEB C3 ret 大家基本上看明白了吧？
将用户名的一位AscII码提出/2 /3 /4 /5.........如果能被他本身整除即为素数.... 总结一下算法：
如：用户名是adyiyd(为什么要加一个a呢？)^o^一会儿就知道了。 字符串： a d y i y d
AscII： 61 64 79 69 79 64
十进制： 97 100 121 105 121 100 注册码=SN
a为素数--->A(将他提出)---(原来a的ASCII码是个素数)^_^
SN=A+((97*4+18)*2+(100*4+18)+(121*4+18)+(105*4+18)+(121*4+18))----(为什么第一位*
2最后一位没有算呢？大家看看上边就清楚了)
SN=A2672 整理一下：
用户名: adyiyd
注册码: A2672 我们一起写一个注册机.... 第一种方法：
用Crackcode2000(具体用法请参考看雪教程)
CRACKCODE.INI中加入
[Options]
CommandLine=ChinaZip.exe
Mode=2
First_Break_Address=4D1E31
First_Break_Address_Code=E8
First_Break_Address_Code_Lenth=5
Second_Break_Address=4040D7
Second_Break_Address_Code_Lenth=2
Save_Code_Address=EDX 第二种方法：
因为本文针对的是初学者，所以用VB编制注册机
源代码如下....
Private Sub Command1_Click() Dim Sum As Long '第二部分总数
Dim StrString As String '第一部分字符串
Dim Strfull As String '输入的用户名
Dim StrPassWord As String '处理后的密码
Dim StrSingle As Integer '单独处理的字符的ASC码值
Dim intLen As Integer '用户名长度
Dim I As Integer, J As Integer
Dim flgFrist As Boolean '标示是否为第一次循环
StrString = ""
Sum = 0
'初始化为第一次循环
flgFrist = True
intLen = Len(Text1(0).Text)
If intLen <= 1 Then
MsgBox "请输入英文字符", vbInformation, "提示"
With Text1(0)
.SelStart = 0
.SelLength = Len(.Text)
.SetFocus
End With
Exit Sub
End If
'处理第二部分数字累加
For I = 1 To intLen - 1
StrSingle = Asc(Mid(Text1(0).Text, I))
'输入中文提示
If StrSingle < 0 Then
MsgBox "请输入英文字符", vbInformation, "提示"
With Text1(0)
.SelStart = 0
.SelLength = Len(.Text)
.SetFocus
End With
'如果为中文,则退出循环
Exit Sub
End If
Sum = Sum + StrSingle * 4 + 18
Next I
StrSingle = Asc(Mid(Text1(0).Text, 1))
Sum = Sum + StrSingle * 4 + 18
'累加和处理结束
StrPassWord = Trim(Str(Sum))
'处理第一部分字符连接
For I = 1 To intLen
StrSingle = Asc(Mid(Text1(0).Text, I))
J = 2
Do While StrSingle Mod J <> 0
If StrSingle = CLng(J) Then
Exit Do
End If
J = J + 1
Loop If StrSingle = CLng(J) Then
StrString = StrString & UCase(Chr(StrSingle))
End If
Next I
Text1(1).Text = Trim(StrString) & Trim(StrPassWord)
With Text1(1)
.SelStart = 0
.SelLength = Len(.Text)
.SetFocus
End With
End Sub 注：本程序没有对中文字符进行处理 这种方法虽然笨一些，但是非常清楚。还是看不懂得朋友看看我家的注视吧!
写了这么多，手已经麻了。还希望大家能够满意
希望和大家多多交流!多提宝贵意见!^_^
注册机我的网页可以下载到
http://dyiyd.yeah.net
dyiyd@yeah.net
|